A gas sample occupies a volume of 8 L at 20 °C. The temperature at which the gas would double its volume is ________.

Question

Quizplus · Accepted Answer

We can use the Gay-Lussac's Law, which states that the pressure of a gas is directly proportional to its temperature at constant volume. Therefore, we can write:
P1/T1 = P2/T2
where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature. We can assume that the pressure is constant, so we can simplify the equation to:
T2 = T1(V2/V1)
where V1 and V2 are the initial and final volumes of the gas, respectively. If we want the gas to double its volume, we need V2 = 2V1. Substituting this into the equation, we get:
T2 = T1(2/1) = 2T1
Converting the initial temperature to Kelvin, we get:
T1 = 20 + 273 = 293 K
Therefore, the temperature at which the gas would double its volume is:
T2 = 2T1 = 2(293) = 586 K. 
Hence, the answer is D.

A Gas Sample Occupies a Volume of 8 L at 20