A gas occupies 2.00 L at 298 K and 2.10 atm. The volume of this quantity of gas at STP conditions is ________.

Question

Quizplus · Accepted Answer

We can use the combined gas law to solve for the volume at STP conditions:

(P1V1/T1) = (P2V2/T2)

We know: 
P1 = 2.10 atm 
V1 = 2.00 L 
T1 = 298 K

At STP, 
P2 = 1 atm 
T2 = 273 K

Plugging in these values:

(2.10 atm * 2.00 L) / 298 K = (1 atm * V2) / 273 K

Solving for V2:

V2 = (1 atm * 2.00 L * 273 K) / (2.10 atm * 298 K)

V2 = 3.84 L

Therefore, the answer is C.

A Gas Occupies 2