What weight of nitrogen gas will occupy a volume of 1.25 L at a pressure of 1 atm and a temperature of 200.°C?

Question

Quizplus · Accepted Answer

Using the ideal gas law, PV = nRT, where P = 1 atm, V = 1.25 L, R = 0.0821 L·atm/mol·K, and T = 473 K (200°C + 273), we can solve for n (moles of nitrogen). n = PV/RT = (1 atm * 1.25 L) / (0.0821 L·atm/mol·K * 473 K) = 0.0322 mol. The molar mass of nitrogen (N2) is 28.02 g/mol, so the weight is 0.0322 mol * 28.02 g/mol = 0.90 g.

What Weight of Nitrogen Gas Will Occupy a Volume of 1.25