25 mL of 0.2 M NaOH will neutralize 10 mL 0.5 M HCl solution.

Question

Quizplus · Accepted Answer

This is a stoichiometry problem involving the reaction between NaOH and HCl. We can start by writing the balanced equation:

NaOH + HCl -> NaCl + H2O

From the equation, we can see that 1 mole of NaOH reacts with 1 mole of HCl. Using the given concentrations and volumes, we can calculate the moles of HCl:

moles of HCl = concentration x volume = 0.5 M x 0.01 L = 0.005 mol

To completely neutralize the HCl, we would need an equal number of moles of NaOH. This can be calculated using the same equation:

moles of NaOH = moles of HCl = 0.005 mol

From here, we can calculate the concentration of the NaOH needed:

concentration of NaOH = moles / volume = 0.005 mol / 0.025 L = 0.2 M

We can see that the concentration of NaOH needed is exactly the same as the concentration given in the problem, so the statement is true.

25 ML of 0