In the reaction N₂H₄ (g)⇔ 2 H₂ (g)+ N₂(g)at 1500 K, the equilibrium concentrations of each species are, [N₂] = 0.10 M, and [N₂H₄] = 0.10 M. The equilibrium constant value is 0.04.

Question

Quizplus · Accepted Answer

The equilibrium constant expression is Kc = ([H₂]^2 [N₂]) / [N₂H₄]. Plugging in the given concentrations and the equilibrium constant value, we get: 0.04 = (0.1^2 x 0.1) / 0.1 0.04 = 0.1 Since this statement is false, the opposite must be true, which is that the statement "The equilibrium constant value is 0.04" is false. The correct equilibrium constant value is actually 4. Therefore, the answer is A.

In the Reaction N2H4 (G)⇔ 2 H2 (G)+ N2 (g)at

In the Reaction N₂H₄ (G)⇔ 2 H₂ (G)+ N₂(g)at