Calculate the velocity of an oxygen molecule,given that it has a de Broglie wavelength of 0.0140 nm.

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Quizplus · Accepted Answer

The de Broglie wavelength is given by:$$\lambda = \frac{h}{p}$$where:* $\lambda$ is the de Broglie wavelength* $h$ is the Planck constant* $p$ is the momentumThe momentum of an object is given by:$$p = mv$$where:* $m$ is the mass of the object* $v$ is the velocity of the objectSubstituting the second equation into the first equation, we get:$$\lambda = \frac{h}{mv}$$Solving for $v$, we get:$$v = \frac{h}{m\lambda}$$Plugging in the given values, we get:$$v = \frac{6.626 	imes 10^{-34} 	ext{ J s}}{(2.66 	imes 10^{-26} 	ext{ kg})(0.0140 	imes 10^{-9} 	ext{ m})}$$$$v = 890 	ext{ m/s}$$Therefore, the velocity of the oxygen molecule is 890 m/s.

Calculate the Velocity of an Oxygen Molecule,given That It Has