How many liters of carbon dioxide measured at 25.0 $\circ$ C and 821 Torr would be produced by the combustion of 319 g of glucose, C 6 H 12 O 6 ?

Question

Quizplus · Accepted Answer

The balanced equation for the combustion of glucose is C6H12O6 + 6O2 → 6CO2 + 6H2O. From 319 g of glucose, which is approximately 1.77 moles (using molar mass ~180 g/mol), 1.77 moles of glucose will produce 1.77 * 6 = 10.62 moles of CO2. Using the ideal gas law at 25°C and 821 Torr, this corresponds to approximately 241 L of CO2.

How Many Liters of Carbon Dioxide Measured at 25 ∘\circ∘ C and 821 Torr Would Be Produced by the Combustion

How Many Liters of Carbon Dioxide Measured at 25 $\circ$ C and 821 Torr Would Be Produced by the Combustion