If 2.00 mol of an ideal gas at 300 K and 3.00 atm expands from 6.00 L to 18.00 L and has a final pressure of 1.20 atm,isothermally and reversibly,which of the following is correct?

Question

Quizplus · Accepted Answer

For an isothermal and reversible expansion of an ideal gas, the change in internal energy ($\Delta$U) is zero. The work done (w) is equal in magnitude and opposite in sign to the heat absorbed (q), so w = -q. The correct calculation for work done is w = -nRT ln(Vf/Vi), which gives -5.48 kJ. Thus, q = +5.48 kJ.

If 200 Mol of an Ideal Gas at 300 K and and 3.00