What mass of propane,C₃H₈(g),must be burned to supply 2580 kJ of heat? The standard enthalpy of combustion of propane at 298 K is -2220 kJ.mol^-1

Question

Quizplus · Accepted Answer

First, we need to use the given standard enthalpy of combustion of propane to convert the energy requirement from kJ to moles of propane:
2580 kJ × 1 mol propane/(-2220 kJ/mol) = -1.162 moles propane (note the negative sign to indicate exothermic combustion)
Next, we can use the molar mass of propane to convert moles to grams:
-1.162 mol propane × 44.1 g/mol = 51.2 g propane
Therefore, the correct answer is B) 51.2 g.

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What Mass of Propane,C₃H₈(g),must Be Burned to Supply 2580 KJ