Calculate Ssurr° at 298 K for the reaction H2(g) + F2(g) 2HF(g)
Hr° = -546 kJ.mol-1, Sr° = +14.1 J.K-1.mol-1
A) +14.1 J.K-1.mol-1
B) +1820 J.K-1.mol-1
C) +1830 J.K-1.mol-1
D) (-1830 J.K-1.mol-1 )
E) (-14.1 J.K-1.mol-1 )
Correct Answer:
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