Calculate the concentration of argon in lake water at 20 $\circ$ C.The partial pressure of argon is 0.0090 atm and Henrys constant is 0.0015 mol.L^-1.atm^-1.

Question

Quizplus · Accepted Answer

Using Henry's Law:

P = kH x [Ar]

0.0090 atm = (0.0015 mol/L/atm) x [Ar]

[Ar] = 0.0090 atm / (0.0015 mol/L/atm) = 6.0 M

However, this answer is in units of Molarity (M) and not in the given format. To convert to the format given, we must convert from M to mol/L as follows:

6.0 M = 6.0 mol/L = 6.0 x 10^10^-3 mol/L = 1.4 x 10^-2 mol/L = 1.4 x 10^10^-2 M

Therefore, the best choice is C with a concentration of 1.4 x 10^-2 M.

Calculate the Concentration of Argon in Lake Water at 20 ∘\circ∘

Calculate the Concentration of Argon in Lake Water at 20^$\circ$