What is the molality of CrCl₃ in a solution prepared by dissolving 75.2 g of chromium(III) chloride hexahydrate in 250.0 g of water.

Question

Quizplus · Accepted Answer

Molality (m) is defined as the number of moles of solute per kilogram of solvent. The formula for chromium(III) chloride hexahydrate is CrCl3•6H2O. Its molar mass is calculated as follows: Cr = 52.00 g/mol, Cl = 35.45 g/mol (x3), and 6H2O = 18.015 g/mol (x6). The total molar mass = 52.00 + (35.45*3) + (18.015*6) = 266.48 g/mol. The number of moles of CrCl3•6H2O = 75.2 g / 266.48 g/mol = 0.282 moles. Since the solvent is 250.0 g of water, which is 0.250 kg, the molality = 0.282 moles / 0.250 kg = 1.13 m.

What Is the Molality of CrCl3 in a Solution Prepared

What Is the Molality of CrCl₃ in a Solution Prepared