The equilibrium constant,K,for the reaction 2HgO(s) → 2Hg(l) + O₂(g)
Is 1.2 * 10^-30.Calculate K for the reaction
1/2O₂(g) + Hg(l) → HgO(s) .

Name: The equilibrium constant,K,for the reaction 2HgO(s) → 2Hg(l)+ O 2 (g) Is 1.2 * 10 -30 .Calculate K for the reaction 1/2O 2 (g)+ Hg(l) → HgO(s).
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Question

The equilibrium constant,K,for the reaction 2HgO(s) → 2Hg(l)+ O₂(g) Is 1.2 * 10^-30.Calculate K for the reaction 1/2O₂(g)+ Hg(l) → HgO(s).

Quizplus · Accepted Answer

The Answer of The equilibrium constant,K,for the reaction 2HgO(s) → 2Hg(l)+ O₂(g) Is 1.2 * 10^-30.Calculate K for the reaction 1/2O₂(g)+ Hg(l) → HgO(s).

The Equilibrium Constant,K,for the Reaction 2HgO(s) → 2Hg(l)+ O2(g)

The Equilibrium Constant,K,for the Reaction 2HgO(s) → 2Hg(l)+ O₂(g)