Write the equilibrium constant for 2NaBr(aq) + Pb(ClO4) 2(aq) →PbBr2(s) + 2NaClO4(aq) .
A) K = [Pb2+][Br-2
B) K = 1/([Pb2+][Br-2)
C) K = [NaClO4]2/([NaBr]2[Pb(ClO4) 2]
D) K = [PbBr2]/([Pb2+][Br-]2)
E) K = 1/([Pb(ClO4) 2][NaBr]2)
Correct Answer:
Verified
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