Consider the reaction PCl₅(g) →PCl₃(g)+ Cl₂(g) At a certain temperature,if the initial concentration of PCl₅(g)is 3.0 M,at equilibrium the concentration of Cl₂(g)is 0.80 M.Calculate the value of K_c at this temperature.

Question

Quizplus · Accepted Answer

The reaction can be represented as:

PCl5(g) ⇌ PCl3(g) + Cl2(g)

Let x be the concentration of Cl2(g) at equilibrium. Then, the concentration of PCl3(g) at equilibrium will also be x, and the concentration of PCl5(g) at equilibrium will be (3.0 - x).

The equilibrium constant can be expressed as:

Kc = [PCl3][Cl2] / [PCl5]

Substituting the equilibrium concentrations, we get:

Kc = (x)(x) / (3.0 - x)

At equilibrium, [Cl2] = 0.80 M, so:

Kc = (0.80)(0.80) / (3.0 - 0.80) = 0.29

Therefore, the answer is B.

Consider the Reaction PCl5(g) →PCl3(g)+ Cl2(g)

Consider the Reaction PCl₅(g) →PCl₃(g)+ Cl₂(g)