The standard potential of the cell Pb(s) |PbSO₄(s) |SO₄²^-(aq) m Pb²⁺(aq) |Pb(s)
Is +0.23 V at 25^$\circ$C.Calculate the equilibrium constant for the reaction of 1 M Pb²⁺(aq) with 1M SO₄²^-(aq) .

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The Answer of The standard potential of the cell Pb(s)|PbSO₄(s)|SO₄²^-(aq)m Pb²⁺(aq)|Pb(s) Is +0.23 V at 25 $\circ$ C.Calculate the equilibrium constant for the reaction of 1 M Pb²⁺(aq)with 1M SO₄²^-(aq).

The Standard Potential of the Cell Pb(s)|PbSO4(s)|SO42-(aq)m Pb2+(aq)|Pb(s) Is +0 ∘\circ∘

The Standard Potential of the Cell Pb(s)|PbSO₄(s)|SO₄²^-(aq)m Pb²⁺(aq)|Pb(s)
Is +0 $\circ$