A second-order reaction has a rate constant of 1.25 M^-1.s^-1.If the initial reactant concentration is 1.0 M,calculate the time required for 90% reaction.

Question

Quizplus · Accepted Answer

The integrated rate law for a second-order reaction is:
1/[A]t = kt + 1/[A]0

Substituting the given values:
1/0.1 = (1.25)(t) + 1/1.0

Solving for t:
t = 7.2 s

Therefore, the time required for 90% reaction is:
t90% = (0.9)(7.2 s) = 6.48 s, which is closest to option B).

A Second-Order Reaction Has a Rate Constant of 1