Suppose a cup of coffee at the campus coffee shop is $2.50 and a cup of hot tea is $1.25 and that a student's beverage budget is $20 per week.If you were going to write an algebraic expression of this budget line of the form $\text { Coffee } = A + B T e a$ .B would be

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The budget line equation is derived from the budget constraint: $2.50 \times \text{Coffee} + 1.25 \times \text{Tea} = 20$. Solving for Coffee in terms of Tea gives $\text{Coffee} = 8 - 0.5 \times \text{Tea}$, so B is -1/2.

Suppose a Cup of Coffee at the Campus Coffee Shop Coffee =A+BTea\text { Coffee } = A + B T e a Coffee =A+BTea

Suppose a Cup of Coffee at the Campus Coffee Shop $\text { Coffee } = A + B T e a$