Exhibit 12-9
A regression and correlation analysis resulted in the following information regarding a dependent variable y) and an independent variable x).
$\begin{array}{ll}
\Sigma \mathrm{X}=90 & \Sigma \mathrm{Y}-{\bar{\mathrm{Y}}) X}-\bar{X})=466 \
\Sigma \mathrm{Y}=170 & \Sigma \mathrm{Y}-\overline{\mathrm{Y}})^{2}=1434 \
\mathrm{n}=10\
\mathrm{SSE}=505.98 & \Sigma \mathrm{X}-\bar{X})^{2}=234
\end{array}$

-Refer to Exhibit 12-9. The sample correlation coefficient equals
A) 0.8045
B) -0.8045
C) 0
D) 1

Question

Exhibit 12-9
A regression and correlation analysis resulted in the following information regarding a dependent variable y) and an independent variable x).
 $\begin{array}{ll}
\Sigma \mathrm{X}=90 & \Sigma \mathrm{Y}-{\bar{\mathrm{Y}}) X}-\bar{X})=466 \
\Sigma \mathrm{Y}=170 & \Sigma \mathrm{Y}-\overline{\mathrm{Y}})^{2}=1434 \
\mathrm{n}=10\
\mathrm{SSE}=505.98 &  \Sigma \mathrm{X}-\bar{X})^{2}=234 
\end{array}$

-Refer to Exhibit 12-9. The sample correlation coefficient equals
A) 0.8045
B) -0.8045
C) 0
D) 1

Quizplus · Accepted Answer

The sample correlation coefficient is the square root of the coefficient of determination, which is given as 0.6477. Taking the square root of 0.6477 gives a value of 0.8045, which is the sample correlation coefficient. Since the correlation coefficient is positive, the answer is A.

Exhibit 12-9 a Regression and Correlation Analysis Resulted in the Following

Exhibit 12-9
a Regression and Correlation Analysis Resulted in the Following