If P(A) = 0.62, P(B) = 0.47, and P(A $\cup$ B) = 0.88; then P(A $\cap$ B) =
A)0.2914
B)1.9700
C)0.6700
D)0.2100

Name: If P(A) = 0.62, P(B) = 0.47, and P(A $\cup$ B) = 0.88; then P(A $\cap$ B) = A)0.2914 B)1.9700 C)0.6700 D)0.2100
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Question

Quizplus · Accepted Answer

The formula for the probability of the intersection of two events is P(A ∩ B) = P(A) + P(B) - P(A ∪ B). Substituting the given values: P(A ∩ B) = 0.62 + 0.47 - 0.88 = 0.21.

If P(A) = 0 ∪\cup∪ B) = 088; Then P(A ∩\cap∩ B) = A)0

If P(A) = 0 $\cup$ B) = 088; Then P(A $\cap$ B) =
A)0