How many moles of PF₃ contain 3.68 × 10²⁵ fluorine atoms?

Question

Quizplus · Accepted Answer

Given the formula PF₃, which translates to PF5, each molecule of PF5 contains 5 fluorine atoms. To find the number of moles of PF5 that contain 3.68 × 10^25 fluorine atoms, divide the total number of fluorine atoms by the number of fluorine atoms in one mole of PF5 (5 atoms × Avogadro's number, 6.022 × 10^23). This calculation gives 3.68 × 10^25 / (5 × 6.022 × 10^23) = 12.2 × 10^1 = 20.4 moles of PF5.

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