How many Fe(II)ions are there in 15.0 g of FeSO₄?

Question

Quizplus · Accepted Answer

To find the number of Fe(II) ions in 15.0 g of FeSO4, first calculate the molar mass of FeSO4 (Fe = 55.85 g/mol, S = 32.07 g/mol, O4 = 4 * 16.00 g/mol = 64.00 g/mol). The total molar mass is 151.91 g/mol. Then, divide the mass of the sample by the molar mass to find the moles of FeSO4 (15.0 g / 151.91 g/mol ≈ 0.0988 mol). Since each formula unit of FeSO4 contains one Fe(II) ion, the number of Fe(II) ions is equal to the number of moles of FeSO4 times Avogadro's number (6.022 × 10^23 mol^-1), which gives approximately 5.94 × 10^22 Fe(II) ions.

How Many Fe(II)ions Are There in 15