Two samples of calcium fluoride are decomposed into their constituent elements.The first sample produced 0.154 g of calcium and 0.146 g of fluorine.If the second sample produced 294 mg of fluorine,how many g of calcium were formed?

Question

Quizplus · Accepted Answer

The ratio of the masses of calcium to fluorine in calcium fluoride (CaF2) is constant due to the law of constant composition. From the first sample, the mass ratio of calcium to fluorine is 0.154 g Ca : 0.146 g F. To find the mass of calcium produced from 294 mg (0.294 g) of fluorine in the second sample, we use the mass ratio from the first sample. $$ \frac{0.154\, \text{g Ca}}{0.146\, \text{g F}} = \frac{x\, \text{g Ca}}{0.294\, \text{g F}} $$Solving for $x$ gives:$$ x = \frac{0.154\, \text{g Ca} \times 0.294\, \text{g F}}{0.146\, \text{g F}} = 0.309\, \text{g Ca} $$Therefore, the correct answer is 0.309 g of calcium, which corresponds to choice D.

Two Samples of Calcium Fluoride Are Decomposed into Their Constituent