According to the following reaction,how many moles of Fe(OH)₂ can form from 175.0 mL of 0.227 M LiOH solution? Assume that there is excess FeCl₂. FeCl₂(aq)+ 2 LiOH(aq)→ Fe(OH)₂(s)+ 2 LiCl(aq) A) 3.97 × 10^-2 moles B) 2.52 × 10^-2 moles C) 1.99 × 10^-2 moles D) 5.03 × 10^-2 moles E) 6.49 × 10^-2 moles

Question

Quizplus · Accepted Answer

First, we need to use the given volume and molarity of LiOH to calculate the number of moles of LiOH:
(0.227 mol/L) x (0.175 L) = 0.0396 mol LiOH
Next, we use the stoichiometry of the balanced equation to determine the number of moles of Fe(OH)2 that can form. For every 2 moles of LiOH, 1 mole of Fe(OH)2 is produced:
0.0396 mol LiOH x (1 mol Fe(OH)2 / 2 mol LiOH) = 0.0198 mol Fe(OH)2
Therefore, the answer is C) 1.99 x 10^-2 moles of Fe(OH)2 can form.

According to the Following Reaction,how Many Moles of Fe(OH)2 Can

According to the Following Reaction,how Many Moles of Fe(OH)₂ Can