If the percent yield for the following reaction is 65.0%,how many grams of KClO₃ are needed to produce 4.00 g of O₂? 2 KClO₃(s)→ 2 KCl(s)+ 3 O₂(g) A) 6.63 g B) 10.2 g C) 15.7 g D) 35.3 g

Question

Quizplus · Accepted Answer

To find the grams of KClO3 needed, first calculate the theoretical yield of O2. Using stoichiometry, 2 moles of KClO3 produce 3 moles of O2. The molar mass of O2 is 32.00 g/mol, so 4.00 g of O2 is 0.125 moles. Therefore, 0.0833 moles of KClO3 are needed (since 2/3 of 0.125 moles). The molar mass of KClO3 is 122.55 g/mol, so 0.0833 moles is 10.2 g. Since the percent yield is 65%, divide 10.2 g by 0.65 to get 15.7 g.

If the Percent Yield for the Following Reaction Is 65