If the percent yield for the following reaction is 75.0%,and 35.0 g of NO₂ are consumed in the reaction,how many grams of nitric acid,HNO₃(aq)are produced? 3 NO₂(g)+ H₂O(l)→ 2 HNO₃(aq)+ NO(g)

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Quizplus · Accepted Answer

Percent yield = (Actual yield/Theoretical yield) x 100%Actual yield = Percent yield x Theoretical yield/100%Actual yield = 75.0% x (35.0 g NO2 x 2 mol HNO3/3 mol NO2 x 63.0 g HNO3/1 mol HNO3)/100%Actual yield = 24.0 g HNO3

If the Percent Yield for the Following Reaction Is 75