Sodium metal and water react to form hydrogen and sodium hydroxide.If 17.94 g of sodium react with water to form 0.78 g of hydrogen and 31.20 g of sodium hydroxide,what mass of water was involved in the reaction?

Question

Quizplus · Accepted Answer

The mass of water involved can be found using the law of conservation of mass. The total mass before the reaction (sodium + water) equals the total mass after the reaction (hydrogen + sodium hydroxide). Given 17.94 g of sodium reacts to form 0.78 g of hydrogen and 31.20 g of sodium hydroxide, the mass of water can be calculated as: mass of water = (0.78 g + 31.20 g) - 17.94 g = 32.98 g - 17.94 g = 14.04 g.

Sodium Metal and Water React to Form Hydrogen and Sodium