When 8.00 × 10²² molecules of ammonia react with 7.00 × 10²² molecules of oxygen according to the chemical equation shown below,how many grams of nitrogen gas are produced? 4 NH₃(g)+ 3 O₂(g)→ 2 N₂(g)+ 6 H₂O(g) A) 1.86 g B) 2.17 g C) 4.88 g D) 7.44 g

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Quizplus · Accepted Answer

The limiting reactant is oxygen, which produces 4.65 × 10^22 molecules of N2. This is equivalent to 1.86 grams of nitrogen gas.

When 800 × 1022 Molecules of Ammonia React with 7

When 800 × 10²² Molecules of Ammonia React with 7