A stock solution of HNO₃ is prepared and found to contain 14.9 M of HNO₃.If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L,the concentration of the diluted solution is ________ M.

Question

Quizplus · Accepted Answer

First, we can use the equation:

C1V1 = C2V2

where C1 is the initial concentration (14.9 M), V1 is the initial volume (25.0 mL = 0.025 L), C2 is the final concentration, and V2 is the final volume (0.500 L).

Solving for C2, we get:

C2 = C1V1/V2 = (14.9 M)(0.025 L)/(0.500 L) = 0.745 M

Therefore, the concentration of the diluted solution is 0.745 M, which corresponds to choice C.

A Stock Solution of HNO3 Is Prepared and Found to Contain

A Stock Solution of HNO₃ Is Prepared and Found to Contain