If the reaction of phosphate ion with water is ignored,what is the total concentration of ions in a solution prepared by dissolving 4.00 g of K₃PO₄ in enough water to make 350.mL of solution? A) 0.0135 M B) 0.0539 M C) 0.215 M D) 0.431 M

Question

Quizplus · Accepted Answer

First, we need to find the number of moles of K₃PO₄ in the solution: molar mass of K₃PO₄ = 174.28 g/mol moles of K₃PO₄ = 4.00 g / 174.28 g/mol = 0.02295 mol Since K₃PO₄ is a salt that dissociates in water, we need to find the concentrations of K+ and SO42- ions separately. K+ ion concentration: Each mole of K₃PO₄ produces one mole of K+ ions, so the concentration of K+ ions in the solution is: 0.02295 mol / 0.350 L = 0.0656 M SO42- ion concentration: Each mole of K₃PO₄ produces one mole of SO42- ions, so the concentration of SO42- ions in the solution is also 0.0656 M. Therefore, the total concentration of ions in the solution is the sum of the concentrations of K+ and SO42- ions: 0.0656 M + 0.0656 M = 0.131 M However, the question states that the reaction of phosphate ion with water is ignored. This means that any phosphate ions that may have been produced by the dissociation of K₃PO₄ are not considered in the calculation. Therefore, the total concentration of ions in the solution is only 0.131 M due to the presence of K+ and SO42- ions. The only answer choice that is close to 0.131 M is C) 0.215 M, which is the best choice.

If the Reaction of Phosphate Ion with Water Is Ignored,what