How many molecules of N₂ are contained in a 10.0 L tank at 7.53 atm and 485 K? A) 1.89 × 10²⁴ molecules B) 1.14 × 10²⁴ molecules C) 8.32 × 10²⁴ molecules D) 4.89 × 10²⁴ molecules E) 3.63 × 10²⁴ molecules

Question

Quizplus · Accepted Answer

To find the number of molecules, we can use the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature. First, we solve for n (moles) and then convert moles to molecules using Avogadro's number (6.022 × 10^23 molecules/mol). Given P = 7.53 atm, V = 10.0 L, T = 485 K, and R = 0.0821 L·atm/(mol·K) (the value of R that matches the units of P, V, and T), we find n and then multiply by Avogadro's number to get the number of molecules. The correct calculation leads to the answer in choice B.

How Many Molecules of N2 Are Contained in a 10

How Many Molecules of N₂ Are Contained in a 10