A mixture of Ar,H₂ and SO₂ has a pressure of 7.85 atm.If the Ar has a mole fraction of 0.47 and H₂ has a mole fraction of 0.23,what is the partial pressure of SO₂?

Question

Quizplus · Accepted Answer

The mole fraction of $SO_2$ can be found by subtracting the mole fractions of Ar and $H_2$ from 1. This gives $1 - 0.47 - 0.23 = 0.30$. The partial pressure of $SO_2$ is then $0.30 \times 7.85 \, \text{atm} = 2.355 \, \text{atm}$, which rounds to 2.4 atm, making option E correct.

A Mixture of Ar,H2 and SO2 Has a Pressure of 7.85

A Mixture of Ar,H₂ and SO₂ Has a Pressure of 7.85