How many liters of oxygen gas can be produced at STP from the decomposition of 0.0625 L of 3.00 M H₂O₂ in the reaction according to the chemical equation shown below? 2 H₂O₂(l)→ 2 H₂O(l)+ O₂(g) A) 2.10 L B) 2.80 L C) 4.20 L D) 8.40 L

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The decomposition of 0.0625 L of 3.00 M H₂O₂ gives 0.1875 moles of H₂O₂. According to the balanced equation, 2 moles of H₂O₂ produce 1 mole of O₂. Therefore, 0.1875 moles of H₂O₂ produce 0.09375 moles of O₂. At STP, 1 mole of gas occupies 22.4 L, so 0.09375 moles of O₂ occupy 2.10 L.

How Many Liters of Oxygen Gas Can Be Produced at STP