Calculate the change in internal energy (ΔE)for a system that is giving off 25.0 kJ of heat and is changing from 12.00 L to 6.00 L in volume at 1.50 atm pressure.(Remember that 101.3 J = 1 L^∙atm) A) +25.9 kJ B) -16.0 kJ C) -25.9 kJ D) -24.1 kJ E) 937 kJ

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Quizplus · Accepted Answer

The change in internal energy (ΔE) is calculated using the formula ΔE = q + w, where q is the heat exchanged and w is the work done. Here, q = -25.0 kJ (since the system is giving off heat). The work done (w) is calculated using w = -PΔV, where P = 1.50 atm and ΔV = (6.00 - 12.00) L = -6.00 L. Converting to joules, w = -1.50 atm * (-6.00 L) * 101.3 J/L∙atm = 911.7 J = 0.9117 kJ. Therefore, ΔE = -25.0 kJ + 0.9117 kJ = -24.0883 kJ, which rounds to -24.1 kJ.

Calculate the Change in Internal Energy (ΔE)for a System That