A piece of iron (mass = 25.0 g)at 398 K is placed in a styrofoam coffee cup containing 25.0 mL of water at 298 K.Assuming that no heat is lost to the cup or the surroundings,what will the final temperature of the water be? The specific heat capacity of iron = 0.449 J/g°C and water = 4.18 J/g°C.

Question

Quizplus · Accepted Answer

The heat lost by the iron will be equal to the heat gained by the water. Using the formula $q = mc\Delta T$, where $q$ is the heat transferred, $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature, we can set the heat lost by iron equal to the heat gained by water and solve for the final temperature. The calculation leads to a final temperature of 308 K.

A Piece of Iron (Mass = 25