The specific heat capacity of liquid mercury is 0.14 J/gK.How many joules of heat are needed to raise the temperature of 7.25 g of mercury from 36.0°C to 75.0°C? A) 2.0 × 10³ J B) 40 J C) 113 J D) 5.0 × 10^-4 J E) 2.1 J

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Quizplus · Accepted Answer

The heat needed can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat in joules, $m$ is the mass in grams, $c$ is the specific heat capacity in J/g°C, and $\Delta T$ is the change in temperature in °C. Plugging in the given values: $q = 7.25 \, \text{g} \times 0.14 \, \text{J/g°C} \times (75.0°C - 36.0°C) = 7.25 \times 0.14 \times 39 = 39.69 \, \text{J}$, which rounds to approximately 40 J.

The Specific Heat Capacity of Liquid Mercury Is 0