The specific heat capacity of liquid water is 4.18 J/g-K.How many joules of heat are needed to raise the temperature of 6.00 g of water from 36.0°C to 75.0°C?

Question

Quizplus · Accepted Answer

We can use the formula Q = m * c * deltaT, where Q is the heat added, m is the mass of the water, c is the specific heat capacity of water, and deltaT is the change in temperature.

Substituting the given values, we get:
Q = 6.00 g * 4.18 J/g-K * (75.0°C - 36.0°C)
Q = 978 J

Therefore, the answer is B. 978 J of heat are needed to raise the temperature of 6.00 g of water from 36.0°C to 75.0°C.

The Specific Heat Capacity of Liquid Water Is 4