According to the following reaction,how much energy is required to decompose 56.0 kg of Fe₃O₄? The molar mass of Fe₃O₄is 231.55 g/mol. Fe₃O₄(s)→ 3 Fe(s)+ 2 O₂(g)ΔH°_rxn= +1118 kJ A) 1.35 × 10⁵ kJ B) 1.07 × 10⁴ kJ C) 2.70 × 10⁵ kJ D) 5.41 × 10⁵ kJ E) 8.11 × 10⁵ kJ

Question

Quizplus · Accepted Answer

To find the energy required, first convert 56.0 kg of Fe₃O₄ to moles: (56,000 g) / (231.55 g/mol) = 241.85 mol. Then, multiply the moles by the ΔH°rxn: 241.85 mol × 1118 kJ/mol = 270,000 kJ or 2.70 × 10⁵ kJ.

According to the Following Reaction,how Much Energy Is Required to Decompose