How much energy is required to heat 36.0 g H₂O from a liquid at 65°C to a gas at 115°C? The following physical data may be useful. ΔH_vap = 40.7 kJ/mol
C_liq = 4.18 J/g^∘C
C_gas= 2.01 J/g^∘C
C_sol = 2.09 J/g^∘C
T_melting= 0^∘C
T_boiling = 100^∘C

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The Answer of How much energy is required to heat 36.0 g H₂O from a liquid at 65°C to a gas at 115°C? The following physical data may be useful. ΔH_vap = 40.7 kJ/mol C_liq = 4.18 J/g^∘C C_gas= 2.01 J/g^∘C C_sol = 2.09 J/g^∘C T_melting= 0^∘C T_boiling = 100^∘C A) 63.5 kJ B) 87.7 kJ C) 10.9 kJ D) 52.7 kJ E) 91.7 kJ

How Much Energy Is Required to Heat 36