A solution is prepared by dissolving 38.6 g sucrose (C₁₂H₂₂O₁₁)in 495 g of water.Determine the mole fraction of sucrose if the final volume of the solution is 508 mL. A) 4.09 × 10^-3 B) 7.80 × 10^-2 C) 1.28 × 10^-3 D) 7.23 × 10^-2 E) 2.45 × 10^-3

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Quizplus · Accepted Answer

The mole fraction of sucrose is calculated by dividing the moles of sucrose by the total moles (moles of sucrose + moles of water). First, calculate the moles of sucrose: the molar mass of sucrose (C12H22O11) is 342.3 g/mol, so 38.6 g of sucrose is 38.6 g / 342.3 g/mol = 0.1128 mol. Then, calculate the moles of water: the molar mass of water (H2O) is 18.015 g/mol, so 495 g of water is 495 g / 18.015 g/mol = 27.48 mol. The total moles = 0.1128 mol (sucrose) + 27.48 mol (water) = 27.593 mol. The mole fraction of sucrose = moles of sucrose / total moles = 0.1128 / 27.593 = 4.09 × 10^-3.

A Solution Is Prepared by Dissolving 38