How many moles of LiBr are contained in 347 g of water in a 0.175 m LiBr solution? A) 1.65 × 10^-2 mol LiBr B) 5.04 × 10^-2 mol LiBr C) 6.07 × 10^-2 mol LiBr D) 3.22 × 10^-2 mol LiBr E) 1.98 × 10^-2 mol LiBr

Question

Quizplus · Accepted Answer

First, we need to calculate the moles of LiBr present in solution using its molarity and the mass of water:

molarity = moles of solute / liters of solution
0.175 mol/L = moles of LiBr / (347 g / 1000 g/1 L)
moles of LiBr = 0.175 mol/L x 0.347 L = 0.060725 mol

Next, we convert the moles of LiBr to the requested units (scientific notation with two significant figures):

moles of LiBr = 6.07 x 10^-2 mol
Answer: C

How Many Moles of LiBr Are Contained in 347 G