How much water must be added to 36.0 g of SrCl₂ to produce a solution that is 35.0 wt% SrCl₂? A) 48.6 g B) 66.9 g C) 97.2 g D) 103 g

Question

Quizplus · Accepted Answer

First, we need to calculate the mass of SrCl2 in the solution:

mass of SrCl2 = (35/100) x total mass of solution
mass of SrCl2 = (35/100) x (36.0 g + mass of water)

Next, we can set up an equation to solve for the mass of water:

36.0 g / (36.0 g + mass of water) = 0.35

Solving for the mass of water, we get:

mass of water = 66.9 g

How Much Water Must Be Added to 36