A rate is equal to 0.0200 M/s.If [A] = 0.100 M and rate = k[A][B]²,what is the new rate if the concentration of [A] is increased to 0.200 M?

Question

Quizplus · Accepted Answer

The rate law is given as rate = k[A][B]. When the concentration of [A] is doubled from 0.100 M to 0.200 M, the rate also doubles because the rate is directly proportional to the concentration of [A] if [B] remains constant. Therefore, the new rate is 0.0400 M/s.

A Rate Is Equal to 0