Consider the following reaction: CH₄(g)+ 2 H₂S(g)⇌ CS₂(g)+ 4 H₂(g) A reaction mixture initially contains 0.50 M CH₄ and 0.75 M H₂S.If the equilibrium concentration of H₂ is 0.44 M,find the equilibrium constant (K_c)for the reaction.

Question

Quizplus · Accepted Answer

To find Kc, use the equilibrium concentrations. Let x be the change in concentration for CH4 and H2S. At equilibrium, [H2] = 0.44 M, so x = 0.11 M. Thus, [CH4] = 0.50 - 0.11 = 0.39 M, [H2S] = 0.75 - 2(0.11) = 0.53 M, [CS2] = 0.11 M. Kc = ([CS2][H2]^4) / ([CH4][H2S]^2) = (0.11 * 0.44^4) / (0.39 * 0.53^2) = 0.038.

Consider the Following Reaction: CH4(g)+ 2 H2S(g)⇌ CS2(g)+ 4 H2(g)

Consider the Following Reaction: CH₄(g)+ 2 H₂S(g)⇌ CS₂(g)+ 4 H₂(g)