Consider the following reaction: NO(g)+ SO₃(g)⇌ NO₂(g)+ SO₂(g) A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO₃.Determine the equilibrium pressure of NO₂ if K_p for the reaction at this temperature is 0.0118.

Question

Quizplus · Accepted Answer

First, write the expression for equilibrium constant: Kp = (PNOS * PSOS12) / PNO Let x be the change in pressure for NOS and SOS: NO(g)+ SO₃(g) ⇌ NO₂(g)+ SO₂(g) Initial: 0.86 atm 0.86 atm 0 0 Change: -x -x +x +x Equilibrium: 0.86-x 0.86-x x x Substitute the equilibrium pressures into the expression for Kp and solve for x: 0.0118 = ((x)(x))/(0.86-x)^2 Solving this equation gives x = 0.086 atm. Therefore, the equilibrium pressures are: P(NOS) = x = 0.086 atm P(SOS) = 0.86 - x = 0.774 atm Thus, the answer is B, 0.084 atm.

Consider the Following Reaction: NO(g)+ SO3(g)⇌ NO2(g)+ SO2(g)

Consider the Following Reaction: NO(g)+ SO₃(g)⇌ NO₂(g)+ SO₂(g)