At a certain temperature the equilibrium constant,K_c,equals 0.11 for the reaction: 2 ICl(g) ⇌ I₂(g) + Cl₂(g) .
What is the equilibrium concentration of ICl if 0.45 mol of I₂ and 0.45 mol of Cl₂ are initially mixed in a 2.0-L flask?

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is:K_c = [I₂][Cl₂]/[ICl]²Substituting the given values into the equilibrium constant expression, we get:0.11 = (0.45 M)(0.45 M)/[ICl]²Solving for [ICl], we get:[ICl] = 0.27 MTherefore, the equilibrium concentration of ICl is 0.27 M.

At a Certain Temperature the Equilibrium Constant,Kc,equals 0

At a Certain Temperature the Equilibrium Constant,K_c,equals 0