Determine the pH of a 0.188 M NH₃ solution at 25°C.The K_bof NH₃ is 1.76 × 10^-5. A) 5.480 B) 2.740 C) 8.520 D) 11.260 E) 12.656

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Quizplus · Accepted Answer

To find the pH, first calculate the pOH using the formula: pOH = -log[OH^-]. For NH3, [OH^-] can be found using the equation: [OH^-] = √(Kb × [NH3]). Then, pOH = -log(√(1.76 × 10^-5 × 0.188)). Finally, pH = 14 - pOH, which gives approximately 11.260.

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