Determine the molar solubility of Fe(OH)₂in pure water.K_sp for Fe(OH)₂= 4.87 × 10^-17. A) 2.44 × 10^-17 M B) 1.62× 10^-17 M C) 4.03 × 10^-9 M D) 3.65 × 10^-6 M E) 2.30 × 10^-6 M

Question

Quizplus · Accepted Answer

The equilibrium equation is:

Fe(OH)2(s) ⇌ Fe2+(aq) + 2OH-(aq)

Ksp = [Fe2+][OH-]2

Molar solubility of Fe(OH)2(s) = x

[Fe2+] = x

[OH-] = 2x

Ksp = 4.87 × 10-17 = x (2x)2

x = molar solubility of Fe(OH)2(s) = 2.30 × 10-6 M.

Therefore, the best choice is E.

Determine the Molar Solubility of Fe(OH)2 in Pure Water

Determine the Molar Solubility of Fe(OH)₂in Pure Water