The molar solubility of ZnS is 1.6 × 10^-12 M in pure water.Calculate the K_sp for ZnS. A) 8.0 × 10^-13 M B) 3.2 × 10^-12 M C) 1.6 × 10^-35 M D) 2.6 × 10^-24 M E) 6.80 × 10^-5 M

Question

Quizplus · Accepted Answer

The solubility product constant, Ksp, is defined by the following equation:

ZnS(s) ↔ Zn2+(aq) + S2-(aq)

Ksp = [Zn2+][S2-]

At equilibrium, the concentration of each ion will be equal to the molar solubility, s:

Ksp = s^2

Substituting the given molar solubility (1.6 × 10^-12 M) into the Ksp expression yields:

Ksp = (1.6 × 10^-12)^2

Ksp = 2.56 × 10^-24 M^2

Therefore, the correct answer is (D) 2.6 × 10^-24 M.

The Molar Solubility of ZnS Is 1