Place the following in order of decreasing standard molar entropy. NaI(s)K₃PO₄(aq)NaI(aq)

Question

Quizplus · Accepted Answer

The general trend for standard molar entropy is that it increases with increasing molecular complexity and disorder. K₃PO₄(aq) is a polyatomic ion and is more complex than NaI(s) and NaI(aq). Therefore, it has the highest standard molar entropy. NaI(aq) is more disordered than NaI(s) because the ions can move more freely in solution, so it would have a higher entropy than NaI(s). Therefore, the correct order is K₃PO₄(aq) > NaI(aq) > NaI(s).

Place the Following in Order of Decreasing Standard Molar Entropy